Eight consecutive numbers are given. If the average of the two numbers that appear in the middle is 6, then the sum of the eight given numbers is:

56 64 72 48

48

Let the no. be    x,  x + 1,  x + 2   …….. x + 7 ATQ,  \(\frac{x+3+x+4}{2}\) =  6 \(\frac{2x+7}{2}\) = 6 x = \(\frac{5}{2}\)   Sum of all no.’s  =  x + x + 1 + x + 2   …………  + x + 7 =  8x + 28 =  8 × \(\frac{5}{2}\)  + 28 =  48