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CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
The maximum value of $z= 40 x+ 50 y $ subject to constraints
$3x+y≤9$
$x+2y ≤ 8$
$x, y ≥0$
occurs at :
(0, 4)
(2, 3)
(3, 0)
(3, 2)
The correct answer is Option (2) → (2, 3)
Maximum at (2, 3) as,
$Z(2,3)=40×2+50×3$
$=230$
Maximum at (2, 3) as,