A and B started their journeys from X to Y and Y to X, respectively. After crossing each other, A and B completed their remaining journey in 6\(\frac{1}{8}\) and 8 h respectively. If speed of A is 32 km/h, find the speed of B (km/h).
Answer & explanation
Correct answer: option 1
Let meeting time = t hours,
speed of A = S1 and speed of B = S2
time taken by A after meeting = t1
time taken by B after meeting = t2,
ATQ,
t1 = 6\(\frac{1}{8}\) = \(\frac{49}{8}\)
t2 = 8
\(\frac{S_1}{S_2}\) = \(\sqrt {\frac{t_2}{t_1}}\)
\(\frac{32}{S_2}\) = \(\sqrt {\frac{\frac{49}{8}}{8}}\)
\(\frac{32}{S_2}\) = \(\sqrt {\frac{64}{49}}\)
\(\frac{32}{S_2}\) = \(\frac{8}{7}\)
S2 = 7 × 4 = 28