CUET Preparation Today
The value of $\tan ^{-1}(-\sqrt{3})+\cos ^{-1}\left(-\frac{1}{2}\right)$ is: |
$\frac{\pi}{3}$ $-\frac{\pi}{3}$ $\frac{2 \pi}{3}$ $\pi$ |
$\frac{\pi}{3}$ |
The correct answer is Option (1) → $\frac{\pi}{3}$ $\tan^{-1}(-\sqrt{3})+\cos^{-1}\left(-\frac{1}{2}\right)$ $=-\tan^{-1}(\sqrt{3})+π-\cos^{-1}\left(\frac{1}{2}\right)$ $=-\frac{π}{3}+π-\frac{π}{3}=\frac{π}{3}$ |
