The value of $\tan ^{-1}(-\sqrt{3})+\cos ^{-1}\left(-\frac{1}{2}\right)$ is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{\pi}{3}$
$\tan^{-1}(-\sqrt{3})+\cos^{-1}\left(-\frac{1}{2}\right)$
$=-\tan^{-1}(\sqrt{3})+π-\cos^{-1}\left(\frac{1}{2}\right)$
$=-\frac{π}{3}+π-\frac{π}{3}=\frac{π}{3}$