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A person travels from P to Q at a speed of 50 km/h and returns by increasing his speed by 60%. What is his average speed for both the trips? |
35.61 km/h 61.53 km/h 31.56 km/h 16.53 km/h |
61.53 km/h |
Initial Speed = 50 km/hr Increased speed = 50 + 60% of 50 50 + \(\frac{3}{5}\) × 50 = 80km/hr Average speed = \(\frac{2ab}{a+b}\) = \(\frac{2 × 50 × 80 }{50+80}\) = 61.53 km/h |
