A person travels from P to Q at a speed of 50 km/h and returns by increasing his speed by 60%. What is his average speed for both the trips?
Answer & explanation
Correct answer: option 2
Initial Speed = 50 km/hr
Increased speed = 50 + 60% of 50
50 + \(\frac{3}{5}\) × 50 = 80km/hr
Average speed = \(\frac{2ab}{a+b}\)
= \(\frac{2 × 50 × 80 }{50+80}\)
= 61.53 km/h