Answer & explanation
Correct answer: option 2
The two gates shown are NAND gates.
The output of first gate is $\bar{A.B}$
Final Output $Y = \bar{\bar{A.B}}= A.B $
Thus the given combination behaves as an AND gate.
Correct answer: option 2
The two gates shown are NAND gates.
The output of first gate is $\bar{A.B}$
Final Output $Y = \bar{\bar{A.B}}= A.B $
Thus the given combination behaves as an AND gate.