If cot θ = \(\sqrt {3}\) + 2, then cosec θ sec θ = ?
Answer & explanation
Correct answer: option 2
cosec θ . sec θ = cot θ + tan θ
cot θ = \(\sqrt {3}\) + 2
tan θ = \(\sqrt {3}\) - 2
cot θ + tan θ = 2\(\sqrt {3}\)
If cot θ = \(\sqrt {3}\) + 2, then cosec θ sec θ = ?
Correct answer: option 2
cosec θ . sec θ = cot θ + tan θ
cot θ = \(\sqrt {3}\) + 2
tan θ = \(\sqrt {3}\) - 2
cot θ + tan θ = 2\(\sqrt {3}\)