CUET Preparation Today
If cot θ = \(\sqrt {3}\) + 2, then cosec θ sec θ = ? |
\(\frac{3\sqrt {3}}{2}\) 2\(\sqrt {3}\) 5\(\frac{\sqrt{3}}{2}\) 6 |
2\(\sqrt {3}\) |
cosec θ . sec θ = cot θ + tan θ cot θ = \(\sqrt {3}\) + 2 tan θ = \(\sqrt {3}\) - 2 cot θ + tan θ = 2\(\sqrt {3}\) |
