The area bounded by the curve \( y=\sin x \) and x-axis between \( x=0 \) and \( x=\pi \) is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 2
On \( [0,\pi] \), \( \sin x\ge 0 \), so the curve stays above the x-axis and the area is the integral itself.
\( \displaystyle \text{Area}=\int_{0}^{\pi}\sin x\,dx \)
\( \displaystyle =\Big[-\cos x\Big]_{0}^{\pi} \)
\( \displaystyle =-\cos\pi+\cos 0 \)
\( \displaystyle =1+1=2 \)
NCERT Exemplar:
Application of Integrals
