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Home/Practice questions/Chemistry
ChemistryInorganic: D and F Block Elements

Arrange the following metals in decreasing order of their melting poi…

Arrange the following metals in decreasing order of their melting points:

(A) Molybdenum

(B) Copper

(C) Tungsten

(D) Manganese

Choose the correct answer from the options given below:

Answer & explanation+

Correct answer: option 4

The correct answer is Option (4) → (C), (A), (D), (B)

Transition metals have high melting points because of strong metallic bonding, in which the (n−1)d electrons take part along with the ns electrons. The melting points follow two trends:

  • Across a series: the melting point rises to a maximum near the middle (d5), where the number of unpaired d electrons is greatest, and then falls. Manganese is an exception with an unusually low melting point, and copper (d10) at the end of the series is low.

  • Down a group: the 4d and 5d metals have much higher melting points than the 3d metals, because their larger d orbitals form stronger metallic bonds.

So the melting points decrease as:

    5d (group 6) > 4d (group 6) > 3d (group 7) > 3d (group 11)
    W > Mo > Mn > Cu

Matching the given metals:

  • (C) Tungsten: 5d, m.p. about 3680 K (highest of all metals)

  • (A) Molybdenum: 4d, m.p. about 2890 K

  • (D) Manganese: 3d, m.p. about 1520 K

  • (B) Copper: 3d, filled d subshell, m.p. about 1360 K

NCERT (2026-27 edition):
Physical Properties – …

Textbook extract

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