Practicing Success
Two biased dice are thrown together. For the first die $P(6)=\frac{1}{2},$ other scores are equally likely. While for the second die, $P(1)=\frac{2}{5}$ and other scores are equally likely then the mean for the probability distribution of " the number of ones seen", will be |
$\frac{6}{5}$ $\frac{3}{5}$ $\frac{4}{5}$ $\frac{1}{2}$ |
$\frac{1}{2}$ |