Practicing Success
Let f : N → N be a function defined as f(x) = 4x + 3 where Y = {y ∈ N: y = 4x + 3 for some x ∈ N}. Show that f is invertible and its inverse is: |
$g(y)=\frac{3y+4}{4}$ $g(y)=4+\frac{y+4}{4}$ $g(y)=\frac{y+3}{4}$ $g(y)=\frac{y-3}{4}$ |
$g(y)=\frac{y-3}{4}$ |
Function is increasing $x=\frac{y-3}{4}=g(y)$ |