If sinθ + \(\frac{1}{sinθ}\) = 2 and 0 < θ ≤ 90° . Find the value of θ .
Answer & explanation
Correct answer: option 1
sinθ + \(\frac{1}{sinθ}\) = 2
Put θ = 90°
⇒ sin90° + \(\frac{1}{sin90°}\) = 2
satisfied the equation ,
so θ = 90°
If sinθ + \(\frac{1}{sinθ}\) = 2 and 0 < θ ≤ 90° . Find the value of θ .
Correct answer: option 1
sinθ + \(\frac{1}{sinθ}\) = 2
Put θ = 90°
⇒ sin90° + \(\frac{1}{sin90°}\) = 2
satisfied the equation ,
so θ = 90°