Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x2 - 21x + 1= 0

 and x > 1, then the value of

x2 + \(\frac{1}{x^2}\) will be:

Options:

443

439

441

445

Correct Answer:

439

Explanation:

If x2 - 21x + 1= 0

Divide by x on both sides,

x +  \(\frac{1}{x}\) = 21

x2 + \(\frac{1}{x^2}\)  = 212 - 2 = 439

 

 

If x + \(\frac{1}{x}\) = a

then, x2 + \(\frac{1}{x^2}\) = a2 - 2