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$∫\frac{dx}{x^2-9}=$ |
$\frac{1}{6}log|\frac{x-3}{x+3}|+C,$ where C is constant of integration $\frac{1}{2}log|\frac{x-3}{x+3}|+C,$ where C is constant of integration $\frac{1}{6}log|\frac{x+9}{x-9}|+C,$ where C is constant of integration $\frac{1}{6}log|\frac{x+3}{x-3}|+C,$ where C is constant of integration |
$\frac{1}{6}log|\frac{x-3}{x+3}|+C,$ where C is constant of integration |
The correct answer is Option (1) → $\frac{1}{6}log|\frac{x-3}{x+3}|+C,$ where C is constant of integration $∫\frac{dx}{x^2-9}=\frac{1}{2×3}\log\left|\frac{x-3}{x+3}\right|+C$ $\frac{1}{6}\log|\frac{x-3}{x+3}|+C$ |
