$∫\frac{dx}{x^2-9}=$
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{6}log|\frac{x-3}{x+3}|+C,$ where C is constant of integration
$∫\frac{dx}{x^2-9}=\frac{1}{2×3}\log\left|\frac{x-3}{x+3}\right|+C$
$\frac{1}{6}\log|\frac{x-3}{x+3}|+C$