In a reaction the concentration of reactant (A) changes from 0.200 mole L-1 to 0.150 mole L-1 in 10 minutes. What is the average rate of reaction during this interval?
Answer & explanation
Correct answer: option 1
C1 = 0.200 mol L-1
C2 = 0.150 mol L-1
t1 = 0
t2 = 10 minutes
Average rate = -\(\frac{[C_2 - C_1]}{[t_2 - t_1]}\) = -\(\frac{0.150 - 0.200}{10}\) = 0.005 mole L-1 min-1