In a reaction the concentration of reactant (A) changes from 0.200 mole L-1 to 0.150 mole L-1 in 10 minutes. What is the average rate of reaction during this interval?

0.005 mole L-1 min-1 0.001 mole L-1 min-1 0.004 mole L-1 min-1 0.002 mole L-1 min-1

0.005 mole L-1 min-1

C1 = 0.200 mol L-1 C2 = 0.150 mol L-1 t1 = 0 t2 = 10 minutes Average rate = -\(\frac{[C_2 - C_1]}{[t_2 - t_1]}\) = -\(\frac{0.150 - 0.200}{10}\) = 0.005 mole L-1 min-1