The S.I unit of mutual inductance, the 'henry' can be written as |
$\frac{ohm}{second}$ $\frac{volt-second}{ampere}$ $\frac{joule}{(ampere)^2}$ $\frac{weber}{ampere}$ |
$\frac{volt-second}{ampere}$ |
The correct answer is Option (2) → $\frac{volt-second}{ampere}$ Induced voltage, $V=M.\frac{dI}{dt}$ $⇒M=\frac{Vdt}{dI}⇒\frac{volt.second}{ampere}$ |