Practicing Success
What will be the input of A and B for the Boolean expression $\overline{(A + B)}.\overline{(A.B)} =1$? |
0, 0 0, 1 1, 0 1, 1 |
0, 0 |
The given Boolean expresion can be written as $Y = \overline{(A + B)}.\overline{(AB)}$ $= (\bar A.\bar B).(\bar A+\bar B) = (\bar A.\bar A).\bar B+\bar A(\bar B.\bar B)$ $=\bar A.\bar B+\bar A.\bar B=\bar A.\bar B$ So, the truth table is |