Two triangles ΔABC and ΔDEF are similar. If AB = 6 cm, BC = 8 cm and DE = 9 cm, find EF.
Answer & explanation
Correct answer: option 1
ΔABC and ΔDEF are similar. Then ,
\(\frac{AB}{BC}\) = \(\frac{DE}{EF}\)
\(\frac{6}{8}\) = \(\frac{9}{EF}\)
\(\frac{3}{4}\) = \(\frac{9}{EF}\)
EF = \(\frac{4 × 9 }{3}\)
= 12 cm