Two triangles ΔABC and ΔDEF are similar. If AB = 6 cm, BC = 8 cm and DE = 9 cm, find EF.

12 cm 9 cm 10 cm 8 cm

12 cm

ΔABC and ΔDEF are similar. Then , \(\frac{AB}{BC}\) = \(\frac{DE}{EF}\) \(\frac{6}{8}\) = \(\frac{9}{EF}\) \(\frac{3}{4}\) = \(\frac{9}{EF}\) EF = \(\frac{4 × 9 }{3}\) = 12 cm