The area of a triangle with vertices (-3, 0), (3, 0) and (0, k) is 9 sq. units. The value of k will be

3 9 -9 6

3

Draw the triangle roughly. Area = \(\frac{1}{2}\) x base x height 9 sq. units = \(\frac{1}{2}\) x (3+3) x (k)