Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart ?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1.5 s
$s_1=\frac{1}{2}gt^2$ and $s_2=\frac{1}{2}g(t-1)^2$
$∴s_1-s_2=10=\frac{1}{2}g[t^2-(t-1)^2]$
$∴ t = 1.5 s$