Practicing Success
Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart ? |
1.0 s 1.5 s 2.0 s 2.5 s |
1.5 s |
The correct answer is Option (2) → 1.5 s $s_1=\frac{1}{2}gt^2$ and $s_2=\frac{1}{2}g(t-1)^2$ $∴s_1-s_2=10=\frac{1}{2}g[t^2-(t-1)^2]$ $∴ t = 1.5 s$ |