Sunit is going towards north, after going 8 km he turns left and goes 6 km. What is the distance of Sunit from initial point.

14 km 10 km 8 km 6 km

10 km

We can see, Sunil is at C point. AB = 8km, BC = 6km and we need to find the distance AC. Here, in Right angle ΔABC: ⇒ AC2 = AB2 + BC2 ⇒ AC2 = 82 + 62 = 64 + 36 = 100 ⇒ AC = 10 km