Sunit is going towards north, after going 8 km he turns left and goes 6 km. What is the distance of Sunit from initial point.
Answer & explanation
Correct answer: option 2
We can see, Sunil is at C point.
AB = 8km, BC = 6km and we need to find the distance AC.
Here, in Right angle ΔABC:
⇒ AC2 = AB2 + BC2
⇒ AC2 = 82 + 62 = 64 + 36 = 100
⇒ AC = 10 km