A man takes 6 hours 40 minutes to walk to a certain place and ride back on a bicycle. He would save 2 hours 30 minutes by riding both ways. How much time would he take to walk both ways?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 9 hours 10 minutes
The trip is made of two equal legs, so the time for one leg each way can be found and then doubled.
Walk one way + ride one way \(=6\) hr 40 min
Ride both ways \(=6\) hr 40 min \(-\) 2 hr 30 min \(=4\) hr 10 min
Ride one way \(=4\) hr 10 min \(\div2=2\) hr 5 min
Walk one way \(=6\) hr 40 min \(-\) 2 hr 5 min \(=4\) hr 35 min
Walk both ways \(=2\times4\) hr 35 min \(=9\) hr 10 min