Practicing Success
Let A = {x : x is a multiple of 3} and B = {x : x is a multiple of 5}. Then A ∩ B is given by |
{3, 6, 9 ...} {5, 10, 15, 20, ...} {15, 30, 45, ...} None of these |
{15, 30, 45, ...} |
Since x ∈ A ∩ B ⇔ x ∈ A and x ∈ B ⇔ x is a multiple of 3 and x is a multiple of 5 ⇔ x is a multiple of 15. Hence A ∩ B = {x | x is a multiple of 15} = {15, 30, 45, …}. Hence (3) is the correct answer. |