Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

Total Power = $15 \times 40W + 5 \times 100W + 5 \times 80W + 1000W$ = 2500W

Capacity of the fuse should be ≥ $\frac{2500W}{220V}$= 11.36

i. e Imin=12 A