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CUET
Physics
Current Electricity
a
b
c
d
Total Power = $15 \times 40W + 5 \times 100W + 5 \times 80W + 1000W$ = 2500W
Capacity of the fuse should be ≥ $\frac{2500W}{220V}$= 11.36
i. e Imin=12 A