The period of the function $f(x) =e^{\{4\{x\}+3\}}$, where {·} denotes the fractional part function is

$\frac{1}{12}$ 1 $\frac{1}{4}$ 4

$\frac{1}{4}$

$f(x) =e^{\{4\{x\}+3\}}=e^{\{4\{x\}\}}$ Clearly $f(\frac{1}{4}+x)=f(x)$