If $λ_{max}$ is 6563 Å, then wave length of second line for Balmer series will be
Answer & explanation
Correct answer: option 1
$\text{Second line of Balmer series corresponds to transition from n= 2 to m=4}$
$ \frac{1}{\lambda} = R(\frac{1}{2^2} - \frac{1}{4^2}) = R(\frac{1}{4} - \frac{1}{16}) = \frac{3R}{16}$
$ \lambda = \frac{16}{3R}$