At what value of x is the function y = \( 4{x}^{ 2 } -5x+1\) attains its minimum value?

-9/8 3/8 7/8 5/8

5/8

\(\frac{dy}{dx}=8x-5\) Put \(\frac{dy}{dx}= 0\) $\Rightarrow 8x - 5= 0 , x = \frac{5}{8}$