At what value of x is the function y = \( 4{x}^{ 2 } -5x+1\) attains its minimum value?
Answer & explanation
Correct answer: option 4
\(\frac{dy}{dx}=8x-5\)
Put \(\frac{dy}{dx}= 0\)
$\Rightarrow 8x - 5= 0 , x = \frac{5}{8}$
At what value of x is the function y = \( 4{x}^{ 2 } -5x+1\) attains its minimum value?
Correct answer: option 4
\(\frac{dy}{dx}=8x-5\)
Put \(\frac{dy}{dx}= 0\)
$\Rightarrow 8x - 5= 0 , x = \frac{5}{8}$