If the 3rd of June, 2003 was a Tuesday, then what would be the day of…

The correct answer is Option (1) → Sunday

1. Calculate the number of years:

From June 3, 2003, to June 3, 2012, is exactly 9 years.

2. Count the Leap Years:

In this interval, we must identify the years that had 366 days (leap years):

• 2004 (Leap year)
• 2008 (Leap year)
• 2012 (Leap year — since June 10 is after February 29, the extra day is included).
• Total Leap Years = 3

3. Calculate Odd Days from Years:

• Each ordinary year has 1 odd day ($365 \div 7$ leaves a remainder of 1).
• Each leap year has 2 odd days ($366 \div 7$ leaves a remainder of 2).
• Formula: $\text{Total Years} + \text{Number of Leap Years}$
• $\text{Odd Days} = 9 + 3 = 12$
• $12 \div 7 = \mathbf{5 \text{ odd days}}$

4. Calculate the difference in days for June:

• From June 3 to June 10 is $10 - 3 = \mathbf{7 \text{ days}}$.
• $7 \div 7 = \mathbf{0 \text{ odd days}}$.

5. Find the final day:

Total odd days = $5 \text{ (from years)} + 0 \text{ (from month days)} = \mathbf{5 \text{ odd days}}$.

Now, count 5 days forward from Tuesday:

1. Wednesday
2. Thursday
3. Friday
4. Saturday
5. Sunday