CUET Preparation Today
$\lim\limits_{x \rightarrow 0} e^{1 / x}$ equals |
does not exist 1 0 infinity |
does not exist |
$\lim\limits_{x \rightarrow 0^{+}} e^{\frac{1}{x}}=\infty, \lim\limits_{x \rightarrow 0^{-}} e^{\frac{1}{x}}=0$ Hence (1) is the correct answer. |
