Practicing Success
Let m be a positive integer and $\Delta_r=\left|\begin{array}{ccc}2 r-1 & m C_r & 1 \\ m^2-1 & 2^m & m+1 \\ \sin ^2\left(m^2\right) & \sin ^2(m) & \sin \left(m^2\right)\end{array}\right|$. Then the value of $\sum\limits_{r=0}^m \Delta_r$ is given by |
0 m2 – 1 2m 2m sin2 (2m) |
0 |
Using concept of summation of determinant. We get R1, R2 are identical so $\sum\limits_{r=0}^m \Delta_r$ is zero. Hence (1) is the correct answer. |