If tanθ = \(\frac{3}{4}\); then the value of \(\frac{cos^2θ(8sinθ + 5cosθ)}{sin^3θ - 2cos^3θ}\) is?
Answer & explanation
Correct answer: option 4
tanθ = \(\frac{3}{4}\)
= \(\frac{cos^2θ(8sinθ + 5cosθ)}{sin^3θ - 2cos^3θ}\)
(divide by cos3θ in numerator and denominator)