If $x^2 +\frac{1}{x^2}= 7 $, then what is the value of $ x^3 +\frac{1}{x^3}$ ?
Answer & explanation
Correct answer: option 2
x2 + \(\frac{1}{x^2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
If $x^2 +\frac{1}{x^2}= 7 $
Then,
x + \(\frac{1}{x}\) = \(\sqrt {7 + 2}\) = 3
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n
$x^3 +\frac{1}{x^3}$ = 33 - 3 × 3 = 18