When a magnet is being brought towards a coil, the emf induced in the coil does not depend on:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → the resistance of the coil
By Faraday's law the induced emf is set by the number of turns and the rate of change of flux through each turn.
\( \displaystyle \varepsilon = -N\,\frac{d\Phi}{dt} \)
The number of turns \( N \) appears directly. The speed of the magnet decides how fast the flux changes, and the pole strength decides how large the flux through the coil is. So all three change the emf.
The resistance of the coil does not appear in this relation. It only decides the induced current \( I = \varepsilon/R \), not the emf itself.
Note: A similar question was also asked in CUET (UG) 2026 on 20-05-2026 (Slot 1).
NCERT (2026-27):
Faraday’s Law of Induction – “… The magnitude of the induced emf in a circuit is equal to the time rate of change of magnetic flux through the circuit.”
Faraday’s Law of Induction – “… In the case of a closely wound coil of N turns, change of flux associated with each turn, is the same. Therefore, the expression for the total induced emf is given by
\( \displaystyle \varepsilon = -N\,\frac{d\Phi_B}{dt} \qquad (6.4) \)
The induced emf can be increased by increasing the number of turns N of a closed coil.”