Practicing Success
If $\left[\begin{array}{cc}2 x+1 & 5 x \\ 0 & y^2+1\end{array}\right]=\left[\begin{array}{cc}x+3 & 10 \\ 0 & 26\end{array}\right]$, then the value of $(x+y)$ is: |
7 and 2 7 and -3 -4 and 2 -4 and 7 |
7 and -3 |
The correct answer is Option (2) → 7 and -3 |