If $\left[\begin{array}{cc}2 x+1 & 5 x \\ 0 & y^2+1\end{array}\right]=\left[\begin{array}{cc}x+3 & 10 \\ 0 & 26\end{array}\right]$, then the value of $(x+y)$ is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 7 and -3
on comparison
$5x=10⇒x=2$
$y^2+1=26⇒y^2=25$
so $y=±5$
$(x+y)=2±5$ = 7 or -3