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In a circle of radius 15 cm, with centre O. PQ and PR are two chords each of length 16 cm. PO intersects chord QR at the point S. The length of OS is? (approx) |
6.46 cm 8.53 cm 9.43 cm 10.46 cm |
6.46 cm |
h = \(\frac{ab}{2r}\)=\(\frac{16×16}{2×15}\)=\(\frac{16×16}{30}\) = 8.53 h + x = 15 8.53 + x = 15 x = 6.46 cm |
