Manoj decided to give 25% of his income to his son A and a certain amount to his son B. If he gave ₹2,208 to B which is 92% of the decided amount and is ₹1,542 less than the amount given to A, then what percent of his total income did Manoj decide to give his son B?
Answer & explanation
Correct answer: option 1
92% of amount of B = 2208
Total amount of B = \(\frac{2208}{92}\) × 100 = 2400
Amount of A = 2208 + 1542 = 3750
According to question ,
25% of Manoj income = 3750
Total of Manoj income = 3750 × 4 = 15000
Percentage of Amount given to B = \(\frac{2400}{15000}\) × 100
= 16%