What is the average of the first 8 numbers multiples of 6 among the natural numbers?
Answer & explanation
Correct answer: option 3
First multiple of 6 = 6 , 8th multiple of 6 = 8 × 6 = 48
Average = \(\frac{First\; term \;+\; Last \;term}{2}\)
= \(\frac{6 \;+\; 48}{2}\)
= \(\frac{54}{2}\) = 27