Let \(R\) be a relation on the set \(N\) of natural numbers defined by \(nRm\) if \(n\) divides \(m\). Then \(R\) is
Answer & explanation
Correct answer: option 4
Given that \(n\) divides \(n\), \(\forall \ n \in \ N\), \(R\) is reflexive.
Let \(n=2\) and \(m=4\) then \(2\ R\ 4\) but not \(4\ R\ 2\). So \(R\) is not symmetric.
\(R\) is transitive since \(n\) divides \(m\) and \(m\) divides \(r\) implies \(n\) divides \(r\)