Let \(R\) be a relation on the set \(N\) of natural numbers defined by  \(nRm\) if \(n\) divides \(m\). Then \(R\) is

Reflexive, transitive but not symmetric

Given that \(n\) divides \(n\), \(\forall \ n \in \ N\), \(R\) is reflexive.

Let \(n=2\) and \(m=4\) then \(2\ R\ 4\) but not \(4\ R\ 2\). So \(R\) is not symmetric.

\(R\) is transitive since \(n\) divides \(m\) and \(m\) divides \(r\) implies \(n\) divides \(r\)