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A pair of dice is thrown, getting a total of 7 is considered a success. Then the probability of success in a single throw is : |
$\frac{5}{36}$ $\frac{4}{36}$ $\frac{6}{36}$ $\frac{7}{36}$ |
$\frac{6}{36}$ |
The correct answer is Option (3) → $\frac{6}{36}$ Total outcomes = $6×6=36$ favourable space → $\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$ ⇒ probability = $\frac{6}{36}$ |
