Osmotic pressure of 0.25 M aqueous solution of urea at 300 K is

The correct answer is Option (2) → 6.225 bar

We can calculate the osmotic pressure (π\piπ) using the formula:

$\pi = MRT$

Where:

• $M = 0.25 \, \text{mol/L}$
• $R = 0.0821 \, \text{L·atm·mol}^{-1}\text{K}^{-1}$ (or we can convert to bar)
• $T = 300 \, \text{K}$

Step 1: Using atm units

$\pi = 0.25 \times 0.0821 \times 300 = 6.15775 \, \text{atm} \approx 6.16 \, \text{atm}$

Step 2: Convert atm → bar

$1 \, \text{atm} \approx 1.013 \, \text{bar}$

$\pi \approx 6.16 \times 1.013 \approx 6.25 \, \text{bar}$