Find the value of \(\frac{8sin45° + 5cos60°}{sin^230° - 2cos^245° + 7tan45°}\)
Answer & explanation
Correct answer: option 4
\(\frac{8sin45° + 5 cos60°}{sin^230° - 2cos^245° + 7tan45°}\)
= \(\frac{\frac{8}{\sqrt{2}} + \frac{5}{2}}{\frac{1}{4} - 2 × \frac{1}{2} + 7}\)
= \(\frac{4\sqrt {2} + \frac{5}{2}}{\frac{1}{4} + 6}\)
= \(\frac{2(8\sqrt {2} + 5)}{25}\)
= \(\frac{2(5 + 8\sqrt {2})}{25}\)