Find the angle between the vectors \(\vec{a}\) and \(\vec{b}\) with magnitude √3 and 2 respectively having \(\vec{a}\).\(\vec{b}\) = √6.
Answer & explanation
Correct answer: option 1
It is given that |\(\vec{a}\)|= √3 and |\(\vec{a}\)| = 2 and \(\vec{a}\).\(\vec{b}\) = √6.
Now, we know that \(\vec{a}\).\(\vec{b}\) = |\(\vec{a}\)|.|\(\vec{b}\)| cos(θ)
⇒cos(θ) = (√6)/ (√3.2)
⇒cos(θ)= 1/√2
⇒θ = cos-1(1/√2)
⇒θ = π/4