Find the angle between the vectors \(\vec{a}\) and \(\vec{b}\) with magnitude √3 and 2 respectively having \(\vec{a}\).\(\vec{b}\) = √6.

π/4

It is given that |\(\vec{a}\)|= √3  and |\(\vec{a}\)| = 2  and  \(\vec{a}\).\(\vec{b}\)  = √6.

Now, we know that \(\vec{a}\).\(\vec{b}\) = |\(\vec{a}\)|.|\(\vec{b}\)|  cos(θ) 

⇒cos(θ) = (√6)/ (√3.2)

⇒cos(θ)= 1/√2

⇒θ = cos^-1(1/√2)

⇒θ = π/4