\(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\sec^{\frac{2}{3}}xcosec^{\frac{4}{3}}xdx=\)
Answer & explanation
Correct answer: option 2
\(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\sec^{\frac{2}{3}}xcosec^{\frac{4}{3}}xdx=\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\frac{\sec^2x}{(\tan x)^\frac{4}{3}}dx\)
Then put \(\tan x=t\)