The current gain of a transistor in common – emitter mode is 49. The change in collector current and emitter current corresponding to the change in base current by 5.0 μA will be:
Answer & explanation
Correct answer: option 1
Here, $β = 49, ΔI_B = 5.0μA$
$∴ ΔI_C = βΔI_B = 49×5.0μA = 245μA$
$ΔI_E = ΔI_B + ΔI_C = 5.0μA+ 245μA = 250μA$