The solution set of the inequality $|3 x| ≥ |6-3 x|$ is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $[1, \infty)$
Given inequality
$|3x|\ge|6-3x|$
Square both sides
$9x^2\ge(6-3x)^2$
$9x^2\ge36-36x+9x^2$
$0\ge36-36x$
$36x\ge36$
$x\ge1$
The solution set is $x\ge1$.