For \(0\leq x\leq \pi\), the area bounded by \(y=x\) and \(y=x+\sin x\) is1\(2\)2\(4\)3\(2\pi\)4\(4\pi\)Answer & explanation+Correct answer: option 2\(\text{Area}=2\left[\int_{0}^{\pi}(x+\sin x)dx-\int_{0}^{\pi}xdx\right]\)
