For $0\leq x\leq \pi$, the area bounde

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Home Questions K72PTHV97B

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Application of Integrals

Question:

For $0\leq x\leq \pi$, the area bounded by $y=x$ and $y=x+\sin x$ is

Options:

$2$

$4$

$2\pi$

$4\pi$

Correct Answer:

$4$

Explanation:

$\text{Area}=2\left[\int_{0}^{\pi}(x+\sin x)dx-\int_{0}^{\pi}xdx\right]$