Practicing Success
Practicing Success
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If $\vec a,\vec b$ and $\vec c$ are unit coplanar vectors then the scalar triple product $[2\vec a-\vec b\,2\vec b-\vec c\,2\vec c-\vec a]$ is equal to: |
0 1 $-\sqrt{3}$ $\sqrt{3}$ |
0 |
If $\vec a,\vec b\&\vec c$ are coplanar, then $2\vec a-\vec b,2\vec b-\vec c\&2\vec c-\vec a$ are coplanar too. $[∴2\vec a-\vec b\,2\vec b-\vec c\,2\vec c-\vec a]=0$ |
