Let O be the center of a circle and AC be its diameter BD is a chord intersecting AC at E. Point A is joined to B and D. If ∠BDS = 60° and ∠AOD = 100°, then ∠BED = ?
Answer & explanation
Correct answer: option 1
∠COD = 80° (linear angle)
In ΔBOD → OB = OD (radius)
∠OBD = ∠ODB
∠OBD = 180° - (80° + 60°) = 40°
∠BEC = 60° + 40° = 100° (exterior angle of ∠BOE)