Practicing Success
If $a+b+c=0$, then the equation $3 a x^2+2 b x+c=0$ has, in the interval (0, 1). |
at least one root at most one root no root none of these |
at least one root |
Consider the polynomial $f(x)$ given by $f(x) =a x^3+b x^2+c x, \quad x \in[0,1]$ $\Rightarrow f^{\prime}(x) =3 a x^2+2 b x+c$ Clearly, $f(x)$, being a polynomial, is continuous on $[0,1]$ and differentiable on $(0,1)$. Also, $f(0)=0$ and $f(1)=a+b+c=0$ [Given] Thus, 0 and 1 are two roots of $f(x)$. Therefore, by the algebraic interpretation of Rolle's theorem, $f^{\prime}(x)=0$ i.e. $3 a x^2+2 b x+c=0$ has at least one root between 0 and 1 . |