In the given figure, the ratio of electric fluxes through surfaces $S_1$ and $S_2$ is

1 : 3

The correct answer is Option (1) → 1 : 3

Given charges:

Inside surface $S_1$: $+2Q$ and $-Q$ → Net charge enclosed = $+Q$

Inside surface $S_2$: $+2Q$, $-Q$, $+3Q$, $-Q$ → Net charge enclosed = $+3Q$

By Gauss’s law, $\phi = \frac{Q_{enclosed}}{\varepsilon_0}$

∴ $\phi_1 : \phi_2 = Q_1 : Q_2 = 1 : 3$

Therefore, $\phi_1 : \phi_2 = 1 : 3$