In the given figure, the ratio of electric fluxes through surfaces $S_1$ and $S_2$ is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 1 : 3
Given charges:
Inside surface $S_1$: $+2Q$ and $-Q$ → Net charge enclosed = $+Q$
Inside surface $S_2$: $+2Q$, $-Q$, $+3Q$, $-Q$ → Net charge enclosed = $+3Q$
By Gauss’s law, $\phi = \frac{Q_{enclosed}}{\varepsilon_0}$
∴ $\phi_1 : \phi_2 = Q_1 : Q_2 = 1 : 3$
Therefore, $\phi_1 : \phi_2 = 1 : 3$